What is the answer to (x^2-1)/(3x+2)=4(x-1) ?

The answer to (x^2-1)/(3x+2)=4(x-1) is x=1,x=-7/11

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(x^2-1)/(3x+2)=4(x-1)

\frac{x ^{2} - 1}{3 x + 2} = 4 (x - 1)

x = 1, x = - \frac{7}{11}

Decimal Notation

x = 1, x = - 0.63636 \dots

Solution steps

\frac{x ^{2} - 1}{3 x + 2} = 4 (x - 1)

Multiply both sides by

3 x + 2

x^{2} - 1 = 4 (x - 1) (3 x + 2)

Solve

x^{2} - 1 = 4 (x - 1) (3 x + 2) : x = 1, x = - \frac{7}{11}

x = 1, x = - \frac{7}{11}

Verify Solutions

Find undefined (singularity) points:

x = - \frac{2}{3}

Combine undefined points with solutions:

x = 1, x = - \frac{7}{11}

1.6003 = \frac{41.74}{x}

\frac{3}{x + 4} = \frac{2}{3 x - 2}

\frac{9}{x} + 6 = \frac{2}{3 x}

\frac{5}{x - 7} = \frac{2}{x - 1}

\frac{3}{x + 4} = 4 + \frac{5}{x - 2}

What is the answer to (x^2-1)/(3x+2)=4(x-1) ?
The answer to (x^2-1)/(3x+2)=4(x-1) is x=1,x=-7/11
Solve for x: (x^2-1)/(3x+2)=4(x-1)
The solution is x=1,x=-7/11