What is the answer to 0=(x^2+3x)/((3x+1)^2) ?

The answer to 0=(x^2+3x)/((3x+1)^2) is x=0,x=-3

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0=(x^2+3x)/((3x+1)^2)

0 = \frac{x ^{2} + 3 x}{( 3 x + 1 ) ^{2}}

x = 0, x = - 3

Solution steps

0 = \frac{x ^{2} + 3 x}{( 3 x + 1 ) ^{2}}

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

0 = x^{2} + 3 x

Solve

0 = x^{2} + 3 x : x = 0, x = - 3

x = 0, x = - 3

Verify Solutions

Find undefined (singularity) points:

x = - \frac{1}{3}

Combine undefined points with solutions:

x = 0, x = - 3

r, F = G \frac{mm}{r ^{2}}

\frac{5}{x} = \frac{2}{x - 3}

\frac{2}{x - 7} = \frac{9}{x + 7}

\frac{x - 2}{3 x + 4} = - 3

\frac{3 x}{x - 4} = 3 + \frac{2}{x}

What is the answer to 0=(x^2+3x)/((3x+1)^2) ?
The answer to 0=(x^2+3x)/((3x+1)^2) is x=0,x=-3
Solve for x: 0=(x^2+3x)/((3x+1)^2)
The solution is x=0,x=-3