What is the answer to (x^3+8)/(x+2)=x^2-2x+4 ?

The answer to (x^3+8)/(x+2)=x^2-2x+4 is x\ne-2

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(x^3+8)/(x+2)=x^2-2x+4

\frac{x ^{3} + 8}{x + 2} = x^{2} - 2 x + 4

x \neq = - 2

Solution steps

\frac{x ^{3} + 8}{x + 2} = x^{2} - 2 x + 4

Simplify

\frac{x ^{3} + 8}{x + 2} : x^{2} - 2 x + 4

x^{2} - 2 x + 4 = x^{2} - 2 x + 4

Both sides are equal

True for all x

Verify Solutions

Find undefined (singularity) points:

x = - 2

Since the equation is undefined for:

- 2

x \neq = - 2

\frac{9}{n} = \frac{8}{n + 3}

\frac{4}{5} = \frac{12}{2 y - 3}

3 x^{- 2} - 5 x^{- 1} - 2 = 0

\frac{2}{x} = 5

x - 2 = \frac{35}{x}

What is the answer to (x^3+8)/(x+2)=x^2-2x+4 ?
The answer to (x^3+8)/(x+2)=x^2-2x+4 is x\ne-2
Solve for x: (x^3+8)/(x+2)=x^2-2x+4
The solution is x\ne-2