What are the solutions to the equation (x+3)(3x+5)=7 ?

The solutions to the equation (x+3)(3x+5)=7 are x=-2/3 ,x=-4

Find the zeros of (x+3)(3x+5)=7

The zeros of (x+3)(3x+5)=7 are x=-2/3 ,x=-4

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(x + 3) (3 x + 5) = 7

x = - \frac{2}{3}, x = - 4

Decimal Notation

x = - 0.66666 \dots, x = - 4

Solution steps

(x + 3) (3 x + 5) = 7

Expand

(x + 3) (3 x + 5) : 3 x^{2} + 14 x + 15

3 x^{2} + 14 x + 15 = 7

Move

7

to the left side

3 x^{2} + 14 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

1 4^{2} - 4 \cdot 3 \cdot 8 = 10

x_{1, 2} = \frac{- 14 \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 14 + 10}{2 \cdot 3}, x_{2} = \frac{- 14 - 10}{2 \cdot 3}

x = \frac{- 14 + 10}{2 \cdot 3} : - \frac{2}{3}

x = \frac{- 14 - 10}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = - 4

∣ 2 x - 7 ∣ - 3 > 2

4 x - x^{3}

(\frac{7}{3})^{- 2}

\frac{5 x - 8}{x - 1} \geq \frac{7 x - 4}{x + 2}

\frac{4}{3} π

What are the solutions to the equation (x+3)(3x+5)=7 ?
The solutions to the equation (x+3)(3x+5)=7 are x=-2/3 ,x=-4
Find the zeros of (x+3)(3x+5)=7
The zeros of (x+3)(3x+5)=7 are x=-2/3 ,x=-4