What is the answer to 1/((x+2)^2)-4=0 ?

The answer to 1/((x+2)^2)-4=0 is x=-3/2 ,x=-5/2

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1/((x+2)^2)-4=0

\frac{1}{( x + 2 ) ^{2}} - 4 = 0

x = - \frac{3}{2}, x = - \frac{5}{2}

Decimal Notation

x = - 1.5, x = - 2.5

Solution steps

\frac{1}{( x + 2 ) ^{2}} - 4 = 0

Multiply both sides by

(x + 2)^{2}

1 - 4 (x + 2)^{2} = 0

Solve

1 - 4 (x + 2)^{2} = 0 : x = - \frac{3}{2}, x = - \frac{5}{2}

x = - \frac{3}{2}, x = - \frac{5}{2}

Verify Solutions

Find undefined (singularity) points:

x = - 2

Combine undefined points with solutions:

x = - \frac{3}{2}, x = - \frac{5}{2}

x, \frac{a x + b}{c x + d} = 2

t, p = \frac{w}{t}

0 = \frac{2 x + 1}{x - 3}

\frac{2 x + 1}{x} = \frac{18}{10}

\frac{3}{( x - 2 )} = 4 - \frac{1}{3}

What is the answer to 1/((x+2)^2)-4=0 ?
The answer to 1/((x+2)^2)-4=0 is x=-3/2 ,x=-5/2
Solve for x: 1/((x+2)^2)-4=0
The solution is x=-3/2 ,x=-5/2