What is the answer to 1/(3x+1)=(-2)/(1-3x) ?

The answer to 1/(3x+1)=(-2)/(1-3x) is x=-1

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1/(3x+1)=(-2)/(1-3x)

\frac{1}{3 x + 1} = \frac{- 2}{1 - 3 x}

x = - 1

Solution steps

\frac{1}{3 x + 1} = \frac{- 2}{1 - 3 x}

Cross multiply

1 - 3 x = - 6 x - 2

Move

1

to the right side

- 3 x = - 6 x - 3

Move

6 x

to the left side

3 x = - 3

Divide both sides by

3

x = - 1

Verify Solutions

Find undefined (singularity) points:

x = - \frac{1}{3}, x = \frac{1}{3}

Combine undefined points with solutions:

x = - 1

x + \frac{1}{x} = - 2

x, y = \frac{2 x + 7}{2 x - 1}

\frac{4}{v} = \frac{v - 6}{v - 4}

k (x) = \frac{- 2 x - 15}{x + 9}, k (- 6 w)

\frac{x + 5}{x} = \frac{4}{5}

What is the answer to 1/(3x+1)=(-2)/(1-3x) ?
The answer to 1/(3x+1)=(-2)/(1-3x) is x=-1
Solve for x: 1/(3x+1)=(-2)/(1-3x)
The solution is x=-1