What is factor x^2((16-x^2)/(4x)) ?

The solution to factor x^2((16-x^2)/(4x)) is -(x(x+4)(x-4))/4

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factor x^2((16-x^2)/(4x))

factor

x^{2} (\frac{16 - x ^{2}}{4 x})

- \frac{x ( x + 4 ) ( x - 4 )}{4}

Solution steps

x^{2} (\frac{16 - x ^{2}}{4 x})

Remove parentheses:

(a) = a

= x^{2} \frac{16 - x ^{2}}{4 x}

\frac{16 - x ^{2}}{4 x} = \frac{- ( x + 4 ) ( x - 4 )}{4 x}

= \frac{- ( x + 4 ) ( x - 4 )}{4 x} x^{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= (- \frac{( x + 4 ) ( x - 4 )}{4 x}) x^{2}

Remove parentheses:

(- a) = - a

= - x^{2} \frac{( x + 4 ) ( x - 4 )}{4 x}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{( x + 4 ) ( x - 4 ) x ^{2}}{4 x}

Cancel the common factor:

x

= - \frac{x ( x + 4 ) ( x - 4 )}{4}

3 n^{2} - 42 n + 147

- \frac{1}{5} b - \frac{2}{5} = - 2

m (a + b) - n (a + b) + p (a + b)

5 x^{2} - 20 x = 65

1 - \frac{25}{169}

What is factor x^2((16-x^2)/(4x)) ?
The solution to factor x^2((16-x^2)/(4x)) is -(x(x+4)(x-4))/4