What is the answer to (z-1)/(z+1)= 2/(z+4) ?

The answer to (z-1)/(z+1)= 2/(z+4) is z=2,z=-3

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(z-1)/(z+1)= 2/(z+4)

\frac{z - 1}{z + 1} = \frac{2}{z + 4}

z = 2, z = - 3

Solution steps

\frac{z - 1}{z + 1} = \frac{2}{z + 4}

Cross multiply

(z - 1) (z + 4) = (z + 1) \cdot 2

Solve

(z - 1) (z + 4) = (z + 1) \cdot 2 : z = 2, z = - 3

z = 2, z = - 3

Verify Solutions

Find undefined (singularity) points:

z = - 1, z = - 4

Combine undefined points with solutions:

z = 2, z = - 3

\frac{33 - x}{5 x} = 2

\frac{3}{x} - \frac{1}{3} = 6

\frac{6}{x} + \frac{8}{x + 5} = 3

\frac{a x + b}{c x + d} = 6

\frac{3}{4} = \frac{21}{x}

What is the answer to (z-1)/(z+1)= 2/(z+4) ?
The answer to (z-1)/(z+1)= 2/(z+4) is z=2,z=-3
Solve for z: (z-1)/(z+1)= 2/(z+4)
The solution is z=2,z=-3