What is the answer to 2x^{-2}-7x^{-1}+6=0 ?

The answer to 2x^{-2}-7x^{-1}+6=0 is x= 2/3 ,x= 1/2

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2x^{-2}-7x^{-1}+6=0

2 x^{- 2} - 7 x^{- 1} + 6 = 0

x = \frac{2}{3}, x = \frac{1}{2}

Solution steps

2 x^{- 2} - 7 x^{- 1} + 6 = 0

Refine

\frac{2}{x ^{2}} - \frac{7}{x} + 6 = 0

Multiply by LCM

2 - 7 x + 6 x^{2} = 0

Solve

2 - 7 x + 6 x^{2} = 0 : x = \frac{2}{3}, x = \frac{1}{2}

x = \frac{2}{3}, x = \frac{1}{2}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{2}{3}, x = \frac{1}{2}

\frac{x ^{2} ( 12 x - 4 )}{4 x + 5} = 0

5 x^{- 2} - 29 x^{- 1} - 6 = 0

\frac{14}{x} = - \frac{2}{3}

7 - \frac{5}{x - 2} = \frac{10}{x + 2}

\frac{5.6}{0.4 - r} = - 8

What is the answer to 2x^{-2}-7x^{-1}+6=0 ?
The answer to 2x^{-2}-7x^{-1}+6=0 is x= 2/3 ,x= 1/2
Solve for x: 2x^{-2}-7x^{-1}+6=0
The solution is x= 2/3 ,x= 1/2