What are the solutions to the equation 3(x-2)^2=9 ?

The solutions to the equation 3(x-2)^2=9 are x=sqrt(3)+2,x=-sqrt(3)+2

Find the zeros of 3(x-2)^2=9

The zeros of 3(x-2)^2=9 are x=sqrt(3)+2,x=-sqrt(3)+2

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3 (x - 2)^{2} = 9

x = 3 + 2, x = - 3 + 2

Decimal Notation

x = 3.73205 \dots, x = 0.26794 \dots

Solution steps

3 (x - 2)^{2} = 9

Divide both sides by

3

(x - 2)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 3 : x = 3 + 2

Solve

x - 2 = - 3 : x = - 3 + 2

The solutions to the quadratic equation are:

x = 3 + 2, x = - 3 + 2

x^{2} + 6 x

(5 x - 2)^{2} = 25

∣ x - 10 ∣ \geq 2

- 9 x = 27

\frac{( \frac{7}{2} - \frac{2}{3} )}{\frac{3}{5}} + \frac{2}{6}

What are the solutions to the equation 3(x-2)^2=9 ?
The solutions to the equation 3(x-2)^2=9 are x=sqrt(3)+2,x=-sqrt(3)+2
Find the zeros of 3(x-2)^2=9
The zeros of 3(x-2)^2=9 are x=sqrt(3)+2,x=-sqrt(3)+2