What is the answer to x^{-2}+6x^{-1}+2=0 ?

The answer to x^{-2}+6x^{-1}+2=0 is x=(-3+sqrt(7))/2 ,x=-(3+sqrt(7))/2

Solve for x: x^{-2}+6x^{-1}+2=0

The solution is x=(-3+sqrt(7))/2 ,x=-(3+sqrt(7))/2

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x^{- 2} + 6 x^{- 1} + 2 = 0

x = \frac{- 3 + 7}{2}, x = - \frac{3 + 7}{2}

Decimal Notation

x = - 0.17712 \dots, x = - 2.82287 \dots

Solution steps

x^{- 2} + 6 x^{- 1} + 2 = 0

Refine

\frac{1}{x ^{2}} + \frac{6}{x} + 2 = 0

Multiply by LCM

1 + 6 x + 2 x^{2} = 0

Solve

1 + 6 x + 2 x^{2} = 0 : x = \frac{- 3 + 7}{2}, x = - \frac{3 + 7}{2}

x = \frac{- 3 + 7}{2}, x = - \frac{3 + 7}{2}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{- 3 + 7}{2}, x = - \frac{3 + 7}{2}

\frac{1}{x} = \frac{2}{x + 6}

\frac{x}{2 + x} = \frac{1}{2}

M, \frac{a}{M} = 4 g - h

\frac{2}{t} - \frac{3 t}{2} = 7

\frac{16}{x} = 0

What is the answer to x^{-2}+6x^{-1}+2=0 ?
The answer to x^{-2}+6x^{-1}+2=0 is x=(-3+sqrt(7))/2 ,x=-(3+sqrt(7))/2
Solve for x: x^{-2}+6x^{-1}+2=0
The solution is x=(-3+sqrt(7))/2 ,x=-(3+sqrt(7))/2