What is the answer to -(2x)/((x^2+1)^2)=0 ?

The answer to -(2x)/((x^2+1)^2)=0 is x=0

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-(2x)/((x^2+1)^2)=0

- \frac{2 x}{( x ^{2} + 1 ) ^{2}} = 0

x = 0

Solution steps

- \frac{2 x}{( x ^{2} + 1 ) ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

2 x = 0

Divide both sides by

2

x = 0

r, s = \frac{a}{1 - r}

\frac{x ^{2} - 9}{x ^{2} - 25} = x + 1

\frac{2}{( x - 1 )} = x

\frac{10}{x} - \frac{12}{x - 3} = - 4

4 x^{- 2} - 15 x^{- 1} - 4 = 0

What is the answer to -(2x)/((x^2+1)^2)=0 ?
The answer to -(2x)/((x^2+1)^2)=0 is x=0
Solve for x: -(2x)/((x^2+1)^2)=0
The solution is x=0