What is the answer to (c^2+c)/(c-1)=6 ?

The answer to (c^2+c)/(c-1)=6 is c=3,c=2

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(c^2+c)/(c-1)=6

\frac{c ^{2} + c}{c - 1} = 6

c = 3, c = 2

Solution steps

\frac{c ^{2} + c}{c - 1} = 6

Multiply both sides by

c - 1

c^{2} + c = 6 (c - 1)

Solve

c^{2} + c = 6 (c - 1) : c = 3, c = 2

c = 3, c = 2

Verify Solutions

Find undefined (singularity) points:

c = 1

Combine undefined points with solutions:

c = 3, c = 2

\frac{2}{3 x} - 2 = \frac{1}{2 x}

x, y = \frac{x - 3}{x + 4}

\frac{y}{2} - \frac{4}{y} = 1

x, z = \frac{y}{x}

\frac{4 p}{7 - p} = 1

What is the answer to (c^2+c)/(c-1)=6 ?
The answer to (c^2+c)/(c-1)=6 is c=3,c=2
Solve for c: (c^2+c)/(c-1)=6
The solution is c=3,c=2