What is the answer to ((4x-1)(2x+3))/(18x-4)=0 ?

The answer to ((4x-1)(2x+3))/(18x-4)=0 is x= 1/4 ,x=-3/2

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((4x-1)(2x+3))/(18x-4)=0

\frac{( 4 x - 1 ) ( 2 x + 3 )}{18 x - 4} = 0

x = \frac{1}{4}, x = - \frac{3}{2}

Solution steps

\frac{( 4 x - 1 ) ( 2 x + 3 )}{18 x - 4} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

(4 x - 1) (2 x + 3) = 0

Solve

(4 x - 1) (2 x + 3) = 0 : x = \frac{1}{4}, x = - \frac{3}{2}

x = \frac{1}{4}, x = - \frac{3}{2}

Verify Solutions

Find undefined (singularity) points:

x = \frac{2}{9}

Combine undefined points with solutions:

x = \frac{1}{4}, x = - \frac{3}{2}

x + \frac{1}{x} = 3

\frac{1}{1 + x ^{2}} = 0

\frac{2}{x} = \frac{10}{25}

\frac{1 0 ^{12}}{10 x} = 10

\frac{5}{2 t} = 4 - \frac{4}{6 t}

What is the answer to ((4x-1)(2x+3))/(18x-4)=0 ?
The answer to ((4x-1)(2x+3))/(18x-4)=0 is x= 1/4 ,x=-3/2
Solve for x: ((4x-1)(2x+3))/(18x-4)=0
The solution is x= 1/4 ,x=-3/2