What are the solutions to the equation 0=(x+2)^2 ?

The solutions to the equation 0=(x+2)^2 are x=-2

Find the zeros of 0=(x+2)^2

The zeros of 0=(x+2)^2 are x=-2

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0 = (x + 2)^{2}

x = - 2

Solution steps

0 = (x + 2)^{2}

Switch sides

(x + 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x + 2 = 0 : x = - 2

The solution to the quadratic equation is:

x = - 2

23 \cdot 32

- ∣ 9 + 3 x ∣ + 3 \leq 0

\frac{e ^{x}}{e ^{y}}

- (- 1) \cdot c^{3} b^{21}

\frac{55}{64}

What are the solutions to the equation 0=(x+2)^2 ?
The solutions to the equation 0=(x+2)^2 are x=-2
Find the zeros of 0=(x+2)^2
The zeros of 0=(x+2)^2 are x=-2