What is the answer to solvefor y,v=y^{-2} ?

The answer to solvefor y,v=y^{-2} is y= 1/(sqrt(v)),y=-1/(sqrt(v));\quad v\ne 0

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solvefor y,v=y^{-2}

solve for

y, v = y^{- 2}

y = \frac{1}{v}, y = - \frac{1}{v}; v \neq = 0

Solution steps

v = y^{- 2}

Refine

v = \frac{1}{y ^{2}}

Multiply both sides by

y^{2}

v y^{2} = 1

Solve

v y^{2} = 1 : y = \frac{1}{v}, y = - \frac{1}{v}; v \neq = 0

y = \frac{1}{v}, y = - \frac{1}{v}; v \neq = 0

\frac{x}{2 x - 1} = \frac{1}{x - 3}

\frac{25}{15} = \frac{40}{x}

\frac{6}{8} = \frac{30}{m}

x, 2 x + 1 = \frac{5}{x + 2}

8 + (\frac{1}{x} - 2) = 80

What is the answer to solvefor y,v=y^{-2} ?
The answer to solvefor y,v=y^{-2} is y= 1/(sqrt(v)),y=-1/(sqrt(v));\quad v\ne 0