What is the answer to 1-1/(x+1)=x+1 ?

The answer to 1-1/(x+1)=x+1 is x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2

Solve for x: 1-1/(x+1)=x+1

The solution is x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2

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1 - \frac{1}{x + 1} = x + 1

x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

Solution steps

1 - \frac{1}{x + 1} = x + 1

Subtract

1

from both sides

1 - \frac{1}{x + 1} - 1 = x + 1 - 1

Simplify

- \frac{1}{x + 1} = x

Multiply both sides by

x + 1

- 1 = x (x + 1)

Solve

- 1 = x (x + 1) : x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

\frac{8}{x} = 0

\frac{x ^{2} - x - 20}{x + 4} = - 9

d, f = \frac{f g}{f + g - d}

\frac{40}{225.061} = \frac{5}{x}

\frac{5}{x - 5} = 5 + \frac{x}{x - 5}

What is the answer to 1-1/(x+1)=x+1 ?
The answer to 1-1/(x+1)=x+1 is x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2
Solve for x: 1-1/(x+1)=x+1
The solution is x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2