What is the answer to ((1-4x^2))/((1-2x))=0 ?

The answer to ((1-4x^2))/((1-2x))=0 is x=-1/2

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((1-4x^2))/((1-2x))=0

\frac{( 1 - 4 x ^{2} )}{( 1 - 2 x )} = 0

x = - \frac{1}{2}

Solution steps

\frac{( 1 - 4 x ^{2} )}{( 1 - 2 x )} = 0

Simplify

\frac{1 - 4 x ^{2}}{1 - 2 x} : 2 x + 1

2 x + 1 = 0

Move

1

to the right side

2 x = - 1

Divide both sides by

2

x = - \frac{1}{2}

Verify Solutions

Find undefined (singularity) points:

x = \frac{1}{2}

Combine undefined points with solutions:

x = - \frac{1}{2}

\frac{3}{x + 2} = \frac{5}{2 x - 7}

\frac{1}{x} - x = 0

1 + \frac{4 x + 2}{2 x} = \frac{5}{x}

0.5 = \frac{1}{x}

M, t = \frac{b}{4 - M ^{3}}

What is the answer to ((1-4x^2))/((1-2x))=0 ?
The answer to ((1-4x^2))/((1-2x))=0 is x=-1/2
Solve for x: ((1-4x^2))/((1-2x))=0
The solution is x=-1/2