What are the solutions to the equation x^2+9x-4=0 ?

The solutions to the equation x^2+9x-4=0 are x=(-9+sqrt(97))/2 ,x=(-9-sqrt(97))/2

Find the zeros of x^2+9x-4=0

The zeros of x^2+9x-4=0 are x=(-9+sqrt(97))/2 ,x=(-9-sqrt(97))/2

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x^{2} + 9 x - 4 = 0

x = \frac{- 9 + 97}{2}, x = \frac{- 9 - 97}{2}

Decimal Notation

x = 0.42442 \dots, x = - 9.42442 \dots

Solution steps

x^{2} + 9 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 4) = 97

x_{1, 2} = \frac{- 9 \pm 97}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 97}{2 \cdot 1}, x_{2} = \frac{- 9 - 97}{2 \cdot 1}

x = \frac{- 9 + 97}{2 \cdot 1} : \frac{- 9 + 97}{2}

x = \frac{- 9 - 97}{2 \cdot 1} : \frac{- 9 - 97}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 97}{2}, x = \frac{- 9 - 97}{2}

c^{2} - 4 c + 3

133 1^{\frac{1}{3}}

x + 5 \geq 2 x

5 (x + 3) - 2 (x - 1) = 20

\frac{2}{5} + p = \frac{4}{5} + \frac{3}{5} p

What are the solutions to the equation x^2+9x-4=0 ?
The solutions to the equation x^2+9x-4=0 are x=(-9+sqrt(97))/2 ,x=(-9-sqrt(97))/2
Find the zeros of x^2+9x-4=0
The zeros of x^2+9x-4=0 are x=(-9+sqrt(97))/2 ,x=(-9-sqrt(97))/2