What is the answer to solvefor y,x=(y-1)/(y+1) ?

The answer to solvefor y,x=(y-1)/(y+1) is y=(-1-x)/(x-1);\quad x\ne 1

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solvefor y,x=(y-1)/(y+1)

solve for

y, x = \frac{y - 1}{y + 1}

y = \frac{- 1 - x}{x - 1}; x \neq = 1

Solution steps

x = \frac{y - 1}{y + 1}

Multiply both sides by

y + 1

x (y + 1) = y - 1

Expand

x (y + 1) : y x + x

y x + x = y - 1

Move

x

to the right side

y x = y - 1 - x

Move

y

to the left side

y x - y = - 1 - x

Factor

y x - y : y (x - 1)

y (x - 1) = - 1 - x

Divide both sides by

x - 1; x \neq = 1

y = \frac{- 1 - x}{x - 1}; x \neq = 1

b, a = \frac{h}{b}

\frac{7}{x + 3} = \frac{4}{12}

\frac{p + 4}{3} = \frac{13}{p - 6}

2 x - \frac{32}{x ^{3}} = 0

r, θ = \frac{3 r + 2}{2 r + 3}

What is the answer to solvefor y,x=(y-1)/(y+1) ?
The answer to solvefor y,x=(y-1)/(y+1) is y=(-1-x)/(x-1);\quad x\ne 1