What is the answer to p(1)=p^{-1}(1) ?

The answer to p(1)=p^{-1}(1) is p=1,p=-1

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p(1)=p^{-1}(1)

p (1) = p^{- 1} (1)

p = 1, p = - 1

Solution steps

p (1) = p^{- 1} (1)

Refine

p = \frac{1}{p}

Multiply both sides by

p

p^{2} = 1

Solve

p^{2} = 1 : p = 1, p = - 1

p = 1, p = - 1

Verify Solutions

Find undefined (singularity) points:

p = 0

Combine undefined points with solutions:

p = 1, p = - 1

\frac{14}{x} = 7

\frac{10}{14} = \frac{90}{5 c - 24}

\frac{7}{2 x} - \frac{1}{4} = - 2

\frac{1}{( x + 1 ) ^{2}} = 0

\frac{2}{x} = \frac{x}{4 x - 6}