What is the answer to ((y+1)^2)/((y-3)^2)=1 ?

The answer to ((y+1)^2)/((y-3)^2)=1 is y=1

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((y+1)^2)/((y-3)^2)=1

\frac{( y + 1 ) ^{2}}{( y - 3 ) ^{2}} = 1

y = 1

Solution steps

\frac{( y + 1 ) ^{2}}{( y - 3 ) ^{2}} = 1

Multiply both sides by

(y - 3)^{2}

(y + 1)^{2} = (y - 3)^{2}

Expand

(y + 1)^{2} : y^{2} + 2 y + 1

Expand

(y - 3)^{2} : y^{2} - 6 y + 9

y^{2} + 2 y + 1 = y^{2} - 6 y + 9

Move

1

to the right side

y^{2} + 2 y = y^{2} - 6 y + 8

Subtract

y^{2} - 6 y

from both sides

y^{2} + 2 y - (y^{2} - 6 y) = y^{2} - 6 y + 8 - (y^{2} - 6 y)

Simplify

8 y = 8

Divide both sides by

8

y = 1

Verify Solutions

Find undefined (singularity) points:

y = 3

Combine undefined points with solutions:

y = 1

\frac{2}{x} + \frac{2}{x + 1} = 3

- \frac{5}{3 x - 7} = \frac{3}{3 x + 1}

t, P = \frac{100 a}{t}

\frac{2}{9} = \frac{8}{x}

\frac{4}{5} = \frac{2 x - 10}{x - 2}

What is the answer to ((y+1)^2)/((y-3)^2)=1 ?
The answer to ((y+1)^2)/((y-3)^2)=1 is y=1
Solve for y: ((y+1)^2)/((y-3)^2)=1
The solution is y=1