What is the answer to (3x+1)/((3x+1)^2+25)=0 ?

The answer to (3x+1)/((3x+1)^2+25)=0 is x=-1/3

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(3x+1)/((3x+1)^2+25)=0

\frac{3 x + 1}{( 3 x + 1 ) ^{2} + 25} = 0

x = - \frac{1}{3}

Decimal Notation

x = - 0.33333 \dots

Solution steps

\frac{3 x + 1}{( 3 x + 1 ) ^{2} + 25} = 0

Simplify

\frac{3 x + 1}{( 3 x + 1 ) ^{2} + 25} : \frac{3 x + 1}{9 x ^{2} + 6 x + 26}

\frac{3 x + 1}{9 x ^{2} + 6 x + 26} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

3 x + 1 = 0

Move

1

to the right side

3 x = - 1

Divide both sides by

3

x = - \frac{1}{3}

- \frac{1}{3} = \frac{1}{1 + c}

\frac{20}{x - 1} = \frac{25}{x}

\frac{3}{8} = \frac{12}{x}

11 x^{- 2} - 35 x^{- 1} + 6 = 0

(\frac{15}{x} + 3) 7 - 9 x = 0

What is the answer to (3x+1)/((3x+1)^2+25)=0 ?
The answer to (3x+1)/((3x+1)^2+25)=0 is x=-1/3
Solve for x: (3x+1)/((3x+1)^2+25)=0
The solution is x=-1/3