What is the answer to x^{-2}= 1/(x^2) ?

The answer to x^{-2}= 1/(x^2) is x\ne 0

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x^{-2}= 1/(x^2)

x^{- 2} = \frac{1}{x ^{2}}

x \neq = 0

Solution steps

x^{- 2} = \frac{1}{x ^{2}}

Refine

\frac{1}{x ^{2}} = \frac{1}{x ^{2}}

Subtract

\frac{1}{x ^{2}}

from both sides

\frac{1}{x ^{2}} - \frac{1}{x ^{2}} = \frac{1}{x ^{2}} - \frac{1}{x ^{2}}

Simplify

0 = 0

Both sides are equal

True for all x

Verify Solutions

Find undefined (singularity) points:

x = 0

Since the equation is undefined for:

0

x \neq = 0

\frac{45 x + 15}{5 + x} = 5 x - 5

F, \frac{d}{F} = j

\frac{4}{x} = \frac{x}{16}

\frac{5}{z - 4} - \frac{2}{z + 4} = 0

\frac{x + 1}{8} = \frac{6}{x - 1}