What is the answer to 1/(x^2-x)=1 ?

The answer to 1/(x^2-x)=1 is x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2

Solve for x: 1/(x^2-x)=1

The solution is x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2

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\frac{1}{x ^{2} - x} = 1

x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

Decimal Notation

x = 1.61803 \dots, x = - 0.61803 \dots

Solution steps

\frac{1}{x ^{2} - x} = 1

Multiply both sides by

x^{2} - x

1 = x^{2} - x

Solve

1 = x^{2} - x : x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

Verify Solutions

Find undefined (singularity) points:

x = 1, x = 0

Combine undefined points with solutions:

x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

x, y = 3 w - \frac{v}{4 x}

\frac{- 8}{7 x} + 1 = \frac{5}{7}

5 x + 2 x^{- 1} = - 11

\frac{4}{6 x + \frac{3 x}{2}} = 1

\frac{12}{x} = 3

What is the answer to 1/(x^2-x)=1 ?
The answer to 1/(x^2-x)=1 is x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2
Solve for x: 1/(x^2-x)=1
The solution is x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2