What is the answer to 1/(m^3)= 8/125 ?

The answer to 1/(m^3)= 8/125 is m= 5/2 ,m=-5/4+(5sqrt(3))/4 i,m=-5/4-(5sqrt(3))/4 i

Solve for m: 1/(m^3)= 8/125

The solution is m= 5/2 ,m=-5/4+(5sqrt(3))/4 i,m=-5/4-(5sqrt(3))/4 i

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\frac{1}{m ^{3}} = \frac{8}{125}

m = \frac{5}{2}, m = - \frac{5}{4} + \frac{5 3}{4} i, m = - \frac{5}{4} - \frac{5 3}{4} i

Solution steps

\frac{1}{m ^{3}} = \frac{8}{125}

Cross multiply

125 = m^{3} \cdot 8

Solve

125 = m^{3} \cdot 8 : m = \frac{5}{2}, m = - \frac{5}{4} + \frac{5 3}{4} i, m = - \frac{5}{4} - \frac{5 3}{4} i

m = \frac{5}{2}, m = - \frac{5}{4} + \frac{5 3}{4} i, m = - \frac{5}{4} - \frac{5 3}{4} i

Verify Solutions

Find undefined (singularity) points:

m = 0

Combine undefined points with solutions:

m = \frac{5}{2}, m = - \frac{5}{4} + \frac{5 3}{4} i, m = - \frac{5}{4} - \frac{5 3}{4} i

x, F = - \frac{K}{x ^{2}}

x, z = \frac{x + y}{x y}

\frac{250}{x} = 0.35

\frac{2}{a} - 2 = \frac{12}{7 a}

y, x = \frac{9}{y}

What is the answer to 1/(m^3)= 8/125 ?
The answer to 1/(m^3)= 8/125 is m= 5/2 ,m=-5/4+(5sqrt(3))/4 i,m=-5/4-(5sqrt(3))/4 i
Solve for m: 1/(m^3)= 8/125
The solution is m= 5/2 ,m=-5/4+(5sqrt(3))/4 i,m=-5/4-(5sqrt(3))/4 i