What is the answer to solvefor y,2x+1/y =3 ?

The answer to solvefor y,2x+1/y =3 is y= 1/(3-2x);\quad x\ne 3/2

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solvefor y,2x+1/y =3

solve for

y, 2 x + \frac{1}{y} = 3

y = \frac{1}{3 - 2 x}; x \neq = \frac{3}{2}

Solution steps

2 x + \frac{1}{y} = 3

Move

2 x

to the right side

\frac{1}{y} = 3 - 2 x

Multiply both sides by

y

1 = 3 y - 2 x y

Switch sides

3 y - 2 x y = 1

Factor

3 y - 2 x y : y (3 - 2 x)

y (3 - 2 x) = 1

Divide both sides by

3 - 2 x; x \neq = \frac{3}{2}

y = \frac{1}{3 - 2 x}; x \neq = \frac{3}{2}

8 x = \frac{1}{x ^{2}}

\frac{9}{8} = \frac{4}{x}

\frac{n}{n + 1} = \frac{3}{5}

\frac{3}{7 - x} = 0

a, 5 q = \frac{f}{a} + G

What is the answer to solvefor y,2x+1/y =3 ?
The answer to solvefor y,2x+1/y =3 is y= 1/(3-2x);\quad x\ne 3/2