What is the answer to 1=(18x^2)/(x^4+81) ?

The answer to 1=(18x^2)/(x^4+81) is x=3,x=-3

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1=(18x^2)/(x^4+81)

1 = \frac{18 x ^{2}}{x ^{4} + 81}

x = 3, x = - 3

Solution steps

1 = \frac{18 x ^{2}}{x ^{4} + 81}

Multiply both sides by

x^{4} + 81

x^{4} + 81 = 18 x^{2}

Solve

x^{4} + 81 = 18 x^{2} : x = 3, x = - 3

x = 3, x = - 3

\frac{5}{x} = \frac{1}{6}

a, g = \frac{( 1 + 2 a )}{a}

\frac{8}{x + 1} = \frac{4}{3}

\frac{7.7}{3.6} = \frac{2.3}{b}

\frac{x}{x + 4} + 1 = - \frac{4}{x + 4}

What is the answer to 1=(18x^2)/(x^4+81) ?
The answer to 1=(18x^2)/(x^4+81) is x=3,x=-3
Solve for x: 1=(18x^2)/(x^4+81)
The solution is x=3,x=-3