What is the answer to 8x^{-3}=64 ?

The answer to 8x^{-3}=64 is x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i

Solve for x: 8x^{-3}=64

The solution is x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i

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8 x^{- 3} = 64

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

Solution steps

8 x^{- 3} = 64

Refine

\frac{8}{x ^{3}} = 64

Multiply both sides by

x^{3}

8 = 64 x^{3}

Solve

8 = 64 x^{3} : x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

\frac{1}{x + 1} = 1 - \frac{x}{3}

103 = \frac{2 x - 3}{10 - 6 x}

\frac{1}{x + 1} + 2 = \frac{7}{x + 1}

\frac{3 x}{x ^{2} - 7 x} = 8

\frac{1}{x + 2} + 5 = \frac{16}{x + 2}

What is the answer to 8x^{-3}=64 ?
The answer to 8x^{-3}=64 is x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i
Solve for x: 8x^{-3}=64
The solution is x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i