What is the answer to 1/(x-3)+1= 1/(x-3) ?

The answer to 1/(x-3)+1= 1/(x-3) is No Solution

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1/(x-3)+1= 1/(x-3)

\frac{1}{x - 3} + 1 = \frac{1}{x - 3}

No Solution

Solution steps

\frac{1}{x - 3} + 1 = \frac{1}{x - 3}

Subtract

\frac{1}{x - 3}

from both sides

\frac{1}{x - 3} + 1 - \frac{1}{x - 3} = \frac{1}{x - 3} - \frac{1}{x - 3}

Simplify

1 = 0

The sides are not equal

No Solution

x - \frac{10}{x} = - 3

- \frac{x}{x + 8} + 7 = \frac{8}{x + 8}

x^{- 2} = 1

x, z = y - \frac{m}{x}

\frac{11}{4 x} + 9 = 3

What is the answer to 1/(x-3)+1= 1/(x-3) ?
The answer to 1/(x-3)+1= 1/(x-3) is No Solution
Solve for x: 1/(x-3)+1= 1/(x-3)
The solution is No Solution