What is the answer to (x^2-9)/(x+3)=x^2-15 ?

The answer to (x^2-9)/(x+3)=x^2-15 is x=4

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(x^2-9)/(x+3)=x^2-15

\frac{x ^{2} - 9}{x + 3} = x^{2} - 15

x = 4

Solution steps

\frac{x ^{2} - 9}{x + 3} = x^{2} - 15

Simplify

\frac{x ^{2} - 9}{x + 3} : x - 3

x - 3 = x^{2} - 15

Solve

x - 3 = x^{2} - 15 : x = 4, x = - 3

x = 4, x = - 3

Verify Solutions

Find undefined (singularity) points:

x = - 3

Since the equation is undefined for:

- 3

x = 4

\frac{1}{x} + \frac{1}{3 x} = 4

\frac{7 x}{8 - 3 x} = 15

- \frac{2}{x - 1} = 4

\frac{x}{x + 1} = \frac{5}{x + 5}

\frac{3}{5} = \frac{15}{x}

What is the answer to (x^2-9)/(x+3)=x^2-15 ?
The answer to (x^2-9)/(x+3)=x^2-15 is x=4
Solve for x: (x^2-9)/(x+3)=x^2-15
The solution is x=4