What is the answer to 2/(g+3)-1/(g+1)=0 ?

The answer to 2/(g+3)-1/(g+1)=0 is g=1

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2/(g+3)-1/(g+1)=0

\frac{2}{g + 3} - \frac{1}{g + 1} = 0

g = 1

Solution steps

\frac{2}{g + 3} - \frac{1}{g + 1} = 0

Multiply by LCM

g - 1 = 0

Move

1

to the right side

g = 1

Verify Solutions

Find undefined (singularity) points:

g = - 3, g = - 1

Combine undefined points with solutions:

g = 1

\frac{x ^{2} - 5 x + 1}{x - 2} = x

\frac{3}{y - 2} - 2 = \frac{1}{y - 1}

\frac{11}{2} = \frac{33}{x}

0.9 = \frac{2.47 x}{1 + 1.47 x}

\frac{4}{x} = 0

What is the answer to 2/(g+3)-1/(g+1)=0 ?
The answer to 2/(g+3)-1/(g+1)=0 is g=1
Solve for g: 2/(g+3)-1/(g+1)=0
The solution is g=1