What is the answer to solvefor y,x=(2y+1)/(y-1) ?

The answer to solvefor y,x=(2y+1)/(y-1) is y=(1+x)/(x-2);\quad x\ne 2

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solvefor y,x=(2y+1)/(y-1)

solve for

y, x = \frac{2 y + 1}{y - 1}

y = \frac{1 + x}{x - 2}; x \neq = 2

Solution steps

x = \frac{2 y + 1}{y - 1}

Multiply both sides by

y - 1

x (y - 1) = 2 y + 1

Expand

x (y - 1) : y x - x

y x - x = 2 y + 1

Move

x

to the right side

y x = 2 y + 1 + x

Move

2 y

to the left side

y x - 2 y = 1 + x

Factor

y x - 2 y : y (x - 2)

y (x - 2) = 1 + x

Divide both sides by

x - 2; x \neq = 2

y = \frac{1 + x}{x - 2}; x \neq = 2

y, x = \frac{2 y + 1}{y - 3}

a^{- 1} = \frac{1}{a}

x^{- 2} - x^{- 1} - 12 = 0

5 \cdot \frac{5 ^{5 x}}{25 x} = 25

\frac{x}{x - 2} + \frac{3}{x - 4} = 1

What is the answer to solvefor y,x=(2y+1)/(y-1) ?
The answer to solvefor y,x=(2y+1)/(y-1) is y=(1+x)/(x-2);\quad x\ne 2