What is the answer to ((x+3)!)/((x+2)!)=2 ?

The answer to ((x+3)!)/((x+2)!)=2 is x=-1

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((x+3)!)/((x+2)!)=2

\frac{( x + 3 ) !}{( x + 2 ) !} = 2

x = - 1

Solution steps

\frac{( x + 3 ) !}{( x + 2 ) !} = 2

Simplify

\frac{( x + 3 ) !}{( x + 2 ) !} : x + 3

x + 3 = 2

Move

3

to the right side

x = - 1

3 x^{- 2} - 8 x^{- 1} - 3 = 0

\frac{6}{5} = \frac{10}{k - 1}

\frac{1}{( x - 2 )} + \frac{x}{3} = 2

\frac{6}{x + 1} = \frac{5}{40}

\frac{- 8}{r + 6} = 4

What is the answer to ((x+3)!)/((x+2)!)=2 ?
The answer to ((x+3)!)/((x+2)!)=2 is x=-1
Solve for x: ((x+3)!)/((x+2)!)=2
The solution is x=-1