What is the answer to 1/(x+1)= 1/(x+1) ?

The answer to 1/(x+1)= 1/(x+1) is x\ne-1

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1/(x+1)= 1/(x+1)

\frac{1}{x + 1} = \frac{1}{x + 1}

x \neq = - 1

Solution steps

\frac{1}{x + 1} = \frac{1}{x + 1}

Subtract

\frac{1}{x + 1}

from both sides

\frac{1}{x + 1} - \frac{1}{x + 1} = \frac{1}{x + 1} - \frac{1}{x + 1}

Simplify

0 = 0

Both sides are equal

True for all x

Verify Solutions

Find undefined (singularity) points:

x = - 1

Since the equation is undefined for:

- 1

x \neq = - 1

5 = \frac{3}{x}

\frac{1}{x - 6} = \frac{x}{x + 8}

8 - \frac{1}{t} = \frac{7}{t ^{2}}

- 1.645 = \frac{( 15 - 12 )}{x}

k = \frac{5}{9 ( f - 32 ) + 273.15}

What is the answer to 1/(x+1)= 1/(x+1) ?
The answer to 1/(x+1)= 1/(x+1) is x\ne-1
Solve for x: 1/(x+1)= 1/(x+1)
The solution is x\ne-1