What is the answer to x/(6+5)= 1/(3-x) ?

The answer to x/(6+5)= 1/(3-x) is x= 3/2-i(sqrt(35))/2 ,x= 3/2+i(sqrt(35))/2

Solve for x: x/(6+5)= 1/(3-x)

The solution is x= 3/2-i(sqrt(35))/2 ,x= 3/2+i(sqrt(35))/2

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\frac{x}{6 + 5} = \frac{1}{3 - x}

x = \frac{3}{2} - i \frac{35}{2}, x = \frac{3}{2} + i \frac{35}{2}

Solution steps

\frac{x}{6 + 5} = \frac{1}{3 - x}

Cross multiply

x (3 - x) = 11

Solve

x (3 - x) = 11 : x = \frac{3}{2} - i \frac{35}{2}, x = \frac{3}{2} + i \frac{35}{2}

x = \frac{3}{2} - i \frac{35}{2}, x = \frac{3}{2} + i \frac{35}{2}

\frac{x}{x - 9} - 3 = - \frac{5}{x - 9}

\frac{6}{5} = \frac{12}{x}

\frac{- 2 x}{x ^{2} + 4} = 0

- \frac{3}{5} = \frac{12}{x}

\frac{3}{x} = \frac{1}{2}

What is the answer to x/(6+5)= 1/(3-x) ?
The answer to x/(6+5)= 1/(3-x) is x= 3/2-i(sqrt(35))/2 ,x= 3/2+i(sqrt(35))/2
Solve for x: x/(6+5)= 1/(3-x)
The solution is x= 3/2-i(sqrt(35))/2 ,x= 3/2+i(sqrt(35))/2