What is the answer to (x^2-4)/(x+4)=0 ?

The answer to (x^2-4)/(x+4)=0 is x=2,x=-2

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(x^2-4)/(x+4)=0

\frac{x ^{2} - 4}{x + 4} = 0

x = 2, x = - 2

Solution steps

\frac{x ^{2} - 4}{x + 4} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} - 4 = 0

Solve

x^{2} - 4 = 0 : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = - 4

Combine undefined points with solutions:

x = 2, x = - 2

\frac{2 x - 3}{x + 1} = \frac{2}{5}

\frac{12}{x} = 0

\frac{12}{x} = 4

\frac{4}{t - 3} = \frac{6}{t + 3}

\frac{1}{x + 3} = 0

What is the answer to (x^2-4)/(x+4)=0 ?
The answer to (x^2-4)/(x+4)=0 is x=2,x=-2
Solve for x: (x^2-4)/(x+4)=0
The solution is x=2,x=-2