What is the answer to solvefor x,x^{-1}=y^2 ?

The answer to solvefor x,x^{-1}=y^2 is x= 1/(y^2);\quad y\ne 0

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solvefor x,x^{-1}=y^2

solve for

x, x^{- 1} = y^{2}

x = \frac{1}{y ^{2}}; y \neq = 0

Solution steps

x^{- 1} = y^{2}

Refine

\frac{1}{x} = y^{2}

Multiply both sides by

x

1 = y^{2} x

Switch sides

y^{2} x = 1

Divide both sides by

y^{2}; y \neq = 0

x = \frac{1}{y ^{2}}; y \neq = 0

\frac{2}{9} = \frac{4}{x + 8}

\frac{3}{x} = \frac{10}{4 x} - 2

40 = \frac{5}{t}

\frac{26}{x} = 0

y, x = \frac{5}{y}

What is the answer to solvefor x,x^{-1}=y^2 ?
The answer to solvefor x,x^{-1}=y^2 is x= 1/(y^2);\quad y\ne 0