What is the answer to (2x^2)/((x+1)-x+1)=0 ?

The answer to (2x^2)/((x+1)-x+1)=0 is x=0

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(2x^2)/((x+1)-x+1)=0

\frac{2 x ^{2}}{( x + 1 ) - x + 1} = 0

x = 0

Solution steps

\frac{2 x ^{2}}{( x + 1 ) - x + 1} = 0

Simplify

\frac{2 x ^{2}}{( x + 1 ) - x + 1} : x^{2}

x^{2} = 0

Solve

x^{2} = 0 : x = 0

x = 0

\frac{7}{4 x - 3} = \frac{2}{x + 3}

k, r = \frac{k}{k - 7}

- 6 + \frac{x}{x - 6} = \frac{1}{x - 6}

\frac{5}{p} + 5 = - 10

\frac{b}{c} = a, c

What is the answer to (2x^2)/((x+1)-x+1)=0 ?
The answer to (2x^2)/((x+1)-x+1)=0 is x=0
Solve for x: (2x^2)/((x+1)-x+1)=0
The solution is x=0