What is the answer to 2x-3-(x^2+1)/(x-2)=-7 ?

The answer to 2x-3-(x^2+1)/(x-2)=-7 is x=3,x=-3

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2x-3-(x^2+1)/(x-2)=-7

2 x - 3 - \frac{x ^{2} + 1}{x - 2} = - 7

x = 3, x = - 3

Solution steps

2 x - 3 - \frac{x ^{2} + 1}{x - 2} = - 7

Move

3

to the right side

2 x - \frac{x ^{2} + 1}{x - 2} = - 4

Multiply both sides by

x - 2

2 x (x - 2) - (x^{2} + 1) = - 4 (x - 2)

Solve

2 x (x - 2) - (x^{2} + 1) = - 4 (x - 2) : x = 3, x = - 3

x = 3, x = - 3

Verify Solutions

Find undefined (singularity) points:

x = 2

Combine undefined points with solutions:

x = 3, x = - 3

x, \frac{x - y}{2 x} = 3

(x) = \frac{x ^{2} - 5 x + 6}{x ^{2} - 4}

\frac{x ^{2}}{x ^{2} - 4} = 0

\frac{39}{x} = 13

f, h = \frac{k - g}{f - 7}

What is the answer to 2x-3-(x^2+1)/(x-2)=-7 ?
The answer to 2x-3-(x^2+1)/(x-2)=-7 is x=3,x=-3
Solve for x: 2x-3-(x^2+1)/(x-2)=-7
The solution is x=3,x=-3