What is the answer to (x+1)/(x^2-3)=3 ?

The answer to (x+1)/(x^2-3)=3 is x=2,x=-5/3

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(x+1)/(x^2-3)=3

\frac{x + 1}{x ^{2} - 3} = 3

x = 2, x = - \frac{5}{3}

Decimal Notation

x = 2, x = - 1.66666 \dots

Solution steps

\frac{x + 1}{x ^{2} - 3} = 3

Multiply both sides by

x^{2} - 3

x + 1 = 3 (x^{2} - 3)

Solve

x + 1 = 3 (x^{2} - 3) : x = 2, x = - \frac{5}{3}

x = 2, x = - \frac{5}{3}

Verify Solutions

Find undefined (singularity) points:

x = 3, x = - 3

Combine undefined points with solutions:

x = 2, x = - \frac{5}{3}

y, x = \frac{3}{2 y - 4}

\frac{3}{z} = \frac{9}{12}

7 - \frac{1}{t} = \frac{6}{t ^{2}}

\frac{x + 2}{x + 1} = \frac{3}{5}

2 x = \frac{3 x ^{2} - 16}{x}

What is the answer to (x+1)/(x^2-3)=3 ?
The answer to (x+1)/(x^2-3)=3 is x=2,x=-5/3
Solve for x: (x+1)/(x^2-3)=3
The solution is x=2,x=-5/3