What is the answer to 1=(12x^4)/(x^2+1) ?

The answer to 1=(12x^4)/(x^2+1) is x= 1/(sqrt(3)),x=-1/(sqrt(3)),x= 1/2 i,x=-1/2 i

Solve for x: 1=(12x^4)/(x^2+1)

The solution is x= 1/(sqrt(3)),x=-1/(sqrt(3)),x= 1/2 i,x=-1/2 i

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1 = \frac{12 x ^{4}}{x ^{2} + 1}

x = \frac{1}{3}, x = - \frac{1}{3}, x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

1 = \frac{12 x ^{4}}{x ^{2} + 1}

Multiply both sides by

x^{2} + 1

x^{2} + 1 = 12 x^{4}

Solve

x^{2} + 1 = 12 x^{4} : x = \frac{1}{3}, x = - \frac{1}{3}, x = \frac{1}{2} i, x = - \frac{1}{2} i

x = \frac{1}{3}, x = - \frac{1}{3}, x = \frac{1}{2} i, x = - \frac{1}{2} i

\frac{x + 1}{x} = 6

\frac{x + 1}{x} = 2

\frac{9}{t - 3} = \frac{t - 4}{t - 3}

\frac{7}{9} = \frac{8}{x}

x^{2} + \frac{1}{x ^{2}} = 66

What is the answer to 1=(12x^4)/(x^2+1) ?
The answer to 1=(12x^4)/(x^2+1) is x= 1/(sqrt(3)),x=-1/(sqrt(3)),x= 1/2 i,x=-1/2 i
Solve for x: 1=(12x^4)/(x^2+1)
The solution is x= 1/(sqrt(3)),x=-1/(sqrt(3)),x= 1/2 i,x=-1/2 i