What is the answer to 7x^{-2}-23x^{-1}+6=0 ?

The answer to 7x^{-2}-23x^{-1}+6=0 is x= 7/2 ,x= 1/3

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7x^{-2}-23x^{-1}+6=0

7 x^{- 2} - 23 x^{- 1} + 6 = 0

x = \frac{7}{2}, x = \frac{1}{3}

Decimal Notation

x = 3.5, x = 0.33333 \dots

Solution steps

7 x^{- 2} - 23 x^{- 1} + 6 = 0

Refine

\frac{7}{x ^{2}} - \frac{23}{x} + 6 = 0

Multiply by LCM

7 - 23 x + 6 x^{2} = 0

Solve

7 - 23 x + 6 x^{2} = 0 : x = \frac{7}{2}, x = \frac{1}{3}

x = \frac{7}{2}, x = \frac{1}{3}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{7}{2}, x = \frac{1}{3}

\frac{4 x}{x + 2} = 7 - \frac{8}{x + 2}

\frac{x - 8}{x - 2} = \frac{- 5}{x}

7 + (\frac{1}{x} - 2) = 28

- \frac{2}{x} + \frac{3}{14 x} = 25

b, a = \frac{a}{b} + 3

What is the answer to 7x^{-2}-23x^{-1}+6=0 ?
The answer to 7x^{-2}-23x^{-1}+6=0 is x= 7/2 ,x= 1/3
Solve for x: 7x^{-2}-23x^{-1}+6=0
The solution is x= 7/2 ,x= 1/3