What is the answer to ((x-2)^2)/(3-2x)=0 ?

The answer to ((x-2)^2)/(3-2x)=0 is x=2

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((x-2)^2)/(3-2x)=0

\frac{( x - 2 ) ^{2}}{3 - 2 x} = 0

x = 2

Solution steps

\frac{( x - 2 ) ^{2}}{3 - 2 x} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

(x - 2)^{2} = 0

Solve

(x - 2)^{2} = 0 : x = 2

x = 2

Verify Solutions

Find undefined (singularity) points:

x = \frac{3}{2}

Combine undefined points with solutions:

x = 2

\frac{27}{15} = \frac{72}{a}

\frac{2}{p} + \frac{3}{p - 1} = 5

(\frac{x + 4}{2 x - 1}) = 2

6 - \frac{3}{x} = \frac{9}{2}

u, y = \frac{u + 1}{u + 2}

What is the answer to ((x-2)^2)/(3-2x)=0 ?
The answer to ((x-2)^2)/(3-2x)=0 is x=2
Solve for x: ((x-2)^2)/(3-2x)=0
The solution is x=2