What is the answer to (n^2(12n-4))/(4n+5)=0 ?

The answer to (n^2(12n-4))/(4n+5)=0 is n=0,n= 1/3

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(n^2(12n-4))/(4n+5)=0

\frac{n ^{2} ( 12 n - 4 )}{4 n + 5} = 0

n = 0, n = \frac{1}{3}

Solution steps

\frac{n ^{2} ( 12 n - 4 )}{4 n + 5} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

n^{2} (12 n - 4) = 0

Solve

n^{2} (12 n - 4) = 0 : n = 0, n = \frac{1}{3}

n = 0, n = \frac{1}{3}

Verify Solutions

Find undefined (singularity) points:

n = - \frac{5}{4}

Combine undefined points with solutions:

n = 0, n = \frac{1}{3}

\frac{x + 1}{x - 2} = 2

\frac{1}{x} = 0.1

2 = x^{- 1}

\frac{1}{x - 2} + 3 = x + 1

2 + \frac{3}{x} = \frac{11}{4}

What is the answer to (n^2(12n-4))/(4n+5)=0 ?
The answer to (n^2(12n-4))/(4n+5)=0 is n=0,n= 1/3
Solve for n: (n^2(12n-4))/(4n+5)=0
The solution is n=0,n= 1/3