What is the answer to solvefor x,y= 1/(x^2) ?

The answer to solvefor x,y= 1/(x^2) is x= 1/(sqrt(y)),x=-1/(sqrt(y));\quad y\ne 0

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solvefor x,y= 1/(x^2)

solve for

x, y = \frac{1}{x ^{2}}

x = \frac{1}{y}, x = - \frac{1}{y}; y \neq = 0

Solution steps

y = \frac{1}{x ^{2}}

Multiply both sides by

x^{2}

y x^{2} = 1

Solve

y x^{2} = 1 : x = \frac{1}{y}, x = - \frac{1}{y}; y \neq = 0

x = \frac{1}{y}, x = - \frac{1}{y}; y \neq = 0

0 = \frac{1}{x + 1}

\frac{x + 1}{3} - \frac{2 - x}{x} = 1

\frac{6}{2 k - 6} = 3

\frac{y + 4}{3 y - 8} = 1

(8 + x)^{- 3} = 64

What is the answer to solvefor x,y= 1/(x^2) ?
The answer to solvefor x,y= 1/(x^2) is x= 1/(sqrt(y)),x=-1/(sqrt(y));\quad y\ne 0