What is the answer to x-2-((x-2)(x-1))/(x-1)=0 ?

The answer to x-2-((x-2)(x-1))/(x-1)=0 is x\ne 1

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x-2-((x-2)(x-1))/(x-1)=0

x - 2 - \frac{( x - 2 ) ( x - 1 )}{x - 1} = 0

x \neq = 1

Solution steps

x - 2 - \frac{( x - 2 ) ( x - 1 )}{x - 1} = 0

Simplify

- \frac{( x - 2 ) ( x - 1 )}{x - 1} : - x + 2

x - 2 - x + 2 = 0

Solve

x - 2 - x + 2 = 0 :

True for all

x

True for all x

Verify Solutions

Find undefined (singularity) points:

x = 1

Since the equation is undefined for:

1

x \neq = 1

\frac{2}{x + 6} + 3 = \frac{x}{x + 6}

f, f^{- 1} (x) = x^{3} + 8

\frac{( n + 2 ) !}{n !} = 12

\frac{6}{x + 3} + \frac{2}{x + 1} = 1

1 - \frac{100}{x ^{2}} = 0

What is the answer to x-2-((x-2)(x-1))/(x-1)=0 ?
The answer to x-2-((x-2)(x-1))/(x-1)=0 is x\ne 1
Solve for x: x-2-((x-2)(x-1))/(x-1)=0
The solution is x\ne 1