What is the answer to (2X}{X+1}=\frac{2X-1)/X ?

The answer to (2X}{X+1}=\frac{2X-1)/X is X=1

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(2X}{X+1}=\frac{2X-1)/X

\frac{2 X}{X + 1} = \frac{2 X - 1}{X}

X = 1

Solution steps

\frac{2 X}{X + 1} = \frac{2 X - 1}{X}

Cross multiply

2 X^{2} = 2 X^{2} + X - 1

Subtract

2 X^{2} + X

from both sides

2 X^{2} - (2 X^{2} + X) = 2 X^{2} + X - 1 - (2 X^{2} + X)

Simplify

- X = - 1

Divide both sides by

- 1

X = 1

Verify Solutions

Find undefined (singularity) points:

X = - 1, X = 0

Combine undefined points with solutions:

X = 1

\frac{3}{x - 2} = \frac{5}{9 x}

77200 = \frac{200000}{2 ( 1 + x )}

\frac{6}{2 x} = 9

\frac{4}{x - 3} + 5 = 2

\frac{- 3}{x - 3} + \frac{2}{x + 7} = 1

What is the answer to (2X}{X+1}=\frac{2X-1)/X ?
The answer to (2X}{X+1}=\frac{2X-1)/X is X=1
Solve for X: (2X}{X+1}=\frac{2X-1)/X
The solution is X=1