What is the answer to 1/(3x^2+3x-4)=-4 ?

The answer to 1/(3x^2+3x-4)=-4 is x=-(1+sqrt(6))/2 ,x=(sqrt(6)-1)/2

Solve for x: 1/(3x^2+3x-4)=-4

The solution is x=-(1+sqrt(6))/2 ,x=(sqrt(6)-1)/2

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\frac{1}{3 x ^{2} + 3 x - 4} = - 4

x = - \frac{1 + 6}{2}, x = \frac{6 - 1}{2}

Decimal Notation

x = - 1.72474 \dots, x = 0.72474 \dots

Solution steps

\frac{1}{3 x ^{2} + 3 x - 4} = - 4

Multiply both sides by

3 x^{2} + 3 x - 4

1 = - 4 (3 x^{2} + 3 x - 4)

Solve

1 = - 4 (3 x^{2} + 3 x - 4) : x = - \frac{1 + 6}{2}, x = \frac{6 - 1}{2}

x = - \frac{1 + 6}{2}, x = \frac{6 - 1}{2}

Verify Solutions

Find undefined (singularity) points:

x = \frac{- 3 + 57}{6}, x = \frac{- 3 - 57}{6}

Combine undefined points with solutions:

x = - \frac{1 + 6}{2}, x = \frac{6 - 1}{2}

\frac{8 x}{x + 1} = 5 - \frac{8}{x + 1}

\frac{200 p - 5000}{200 p} = 0.3

\frac{20}{x} = 0

b = \frac{( 3 x + 5 )}{( 2 x + 1 )}

\frac{5}{x} + \frac{3}{x} = 24

What is the answer to 1/(3x^2+3x-4)=-4 ?
The answer to 1/(3x^2+3x-4)=-4 is x=-(1+sqrt(6))/2 ,x=(sqrt(6)-1)/2
Solve for x: 1/(3x^2+3x-4)=-4
The solution is x=-(1+sqrt(6))/2 ,x=(sqrt(6)-1)/2