What is the answer to (7x-3)/(x^2+9)=1 ?

The answer to (7x-3)/(x^2+9)=1 is x=4,x=3

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(7x-3)/(x^2+9)=1

\frac{7 x - 3}{x ^{2} + 9} = 1

x = 4, x = 3

Solution steps

\frac{7 x - 3}{x ^{2} + 9} = 1

Multiply both sides by

x^{2} + 9

7 x - 3 = x^{2} + 9

Solve

7 x - 3 = x^{2} + 9 : x = 4, x = 3

x = 4, x = 3

a, \frac{a + b}{a - 3 b} = 5

- \frac{8}{x + 3} = 0

\frac{8}{x} = \frac{12}{x + 20}

F, R = \frac{F}{N + F}

\frac{6}{5} = \frac{2}{5 n}

What is the answer to (7x-3)/(x^2+9)=1 ?
The answer to (7x-3)/(x^2+9)=1 is x=4,x=3
Solve for x: (7x-3)/(x^2+9)=1
The solution is x=4,x=3